Optimal. Leaf size=505 \[ -\frac {\left (a^3 C d^3-3 a^2 b d^2 (2 B d+c C)+3 a b^2 d \left (-8 d^2 (A-C)-4 B c d+c^2 C\right )-\left (b^3 \left (8 c d^2 (A-C)-2 B c^2 d-16 B d^3+c^3 C\right )\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c+d \tan (e+f x)}}\right )}{8 b^{3/2} d^{5/2} f}+\frac {\sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)} \left (8 b d^2 (a B+A b-b C)+(b c-a d) (-a C d-2 b B d+b c C)\right )}{8 b d^2 f}-\frac {(a-i b)^{3/2} \sqrt {c-i d} (i A+B-i C) \tanh ^{-1}\left (\frac {\sqrt {c-i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a-i b} \sqrt {c+d \tan (e+f x)}}\right )}{f}+\frac {(a+i b)^{3/2} \sqrt {c+i d} (i A-B-i C) \tanh ^{-1}\left (\frac {\sqrt {c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{f}-\frac {(-a C d-2 b B d+b c C) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{4 d^2 f}+\frac {C (a+b \tan (e+f x))^{3/2} (c+d \tan (e+f x))^{3/2}}{3 d f} \]
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Rubi [A] time = 7.34, antiderivative size = 505, normalized size of antiderivative = 1.00, number of steps used = 15, number of rules used = 8, integrand size = 49, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.163, Rules used = {3647, 3655, 6725, 63, 217, 206, 93, 208} \[ -\frac {\left (-3 a^2 b d^2 (2 B d+c C)+a^3 C d^3+3 a b^2 d \left (-8 d^2 (A-C)-4 B c d+c^2 C\right )+b^3 \left (-\left (8 c d^2 (A-C)-2 B c^2 d-16 B d^3+c^3 C\right )\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c+d \tan (e+f x)}}\right )}{8 b^{3/2} d^{5/2} f}+\frac {\sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)} \left (8 b d^2 (a B+A b-b C)+(b c-a d) (-a C d-2 b B d+b c C)\right )}{8 b d^2 f}-\frac {(a-i b)^{3/2} \sqrt {c-i d} (i A+B-i C) \tanh ^{-1}\left (\frac {\sqrt {c-i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a-i b} \sqrt {c+d \tan (e+f x)}}\right )}{f}+\frac {(a+i b)^{3/2} \sqrt {c+i d} (i A-B-i C) \tanh ^{-1}\left (\frac {\sqrt {c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{f}-\frac {(-a C d-2 b B d+b c C) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{4 d^2 f}+\frac {C (a+b \tan (e+f x))^{3/2} (c+d \tan (e+f x))^{3/2}}{3 d f} \]
Antiderivative was successfully verified.
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Rule 63
Rule 93
Rule 206
Rule 208
Rule 217
Rule 3647
Rule 3655
Rule 6725
Rubi steps
\begin {align*} \int (a+b \tan (e+f x))^{3/2} \sqrt {c+d \tan (e+f x)} \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right ) \, dx &=\frac {C (a+b \tan (e+f x))^{3/2} (c+d \tan (e+f x))^{3/2}}{3 d f}+\frac {\int \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)} \left (-\frac {3}{2} (b c C-a (2 A-C) d)+3 (A b+a B-b C) d \tan (e+f x)-\frac {3}{2} (b c C-2 b B d-a C d) \tan ^2(e+f x)\right ) \, dx}{3 d}\\ &=-\frac {(b c C-2 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{4 d^2 f}+\frac {C (a+b \tan (e+f x))^{3/2} (c+d \tan (e+f x))^{3/2}}{3 d f}+\frac {\int \frac {\sqrt {c+d \tan (e+f x)} \left (\frac {3}{4} \left (a^2 (8 A-7 C) d^2+b^2 c (c C-2 B d)-2 a b d (c C+3 B d)\right )+6 \left (a^2 B-b^2 B+2 a b (A-C)\right ) d^2 \tan (e+f x)+\frac {3}{4} \left (8 b (A b+a B-b C) d^2+(b c-a d) (b c C-2 b B d-a C d)\right ) \tan ^2(e+f x)\right )}{\sqrt {a+b \tan (e+f x)}} \, dx}{6 d^2}\\ &=\frac {\left (8 b (A b+a B-b C) d^2+(b c-a d) (b c C-2 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{8 b d^2 f}-\frac {(b c C-2 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{4 d^2 f}+\frac {C (a+b \tan (e+f x))^{3/2} (c+d \tan (e+f x))^{3/2}}{3 d f}+\frac {\int \frac {-\frac {3}{8} \left (a^3 C d^3-a^2 b d^2 (16 A c-13 c C-10 B d)-b^3 c \left (c^2 C-2 B c d-8 (A-C) d^2\right )+a b^2 d \left (3 c^2 C+20 B c d+8 (A-C) d^2\right )\right )+6 b d^2 \left (2 a b (A c-c C-B d)+a^2 (B c+(A-C) d)-b^2 (B c+(A-C) d)\right ) \tan (e+f x)+\frac {3}{8} \left (16 b \left (a^2 B-b^2 B+2 a b (A-C)\right ) d^3+(b c-a d) \left (8 b (A b+a B-b C) d^2+(b c-a d) (b c C-2 b B d-a C d)\right )\right ) \tan ^2(e+f x)}{\sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}} \, dx}{6 b d^2}\\ &=\frac {\left (8 b (A b+a B-b C) d^2+(b c-a d) (b c C-2 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{8 b d^2 f}-\frac {(b c C-2 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{4 d^2 f}+\frac {C (a+b \tan (e+f x))^{3/2} (c+d \tan (e+f x))^{3/2}}{3 d f}+\frac {\operatorname {Subst}\left (\int \frac {-\frac {3}{8} \left (a^3 C d^3-a^2 b d^2 (16 A c-13 c C-10 B d)-b^3 c \left (c^2 C-2 B c d-8 (A-C) d^2\right )+a b^2 d \left (3 c^2 C+20 B c d+8 (A-C) d^2\right )\right )+6 b d^2 \left (2 a b (A c-c C-B d)+a^2 (B c+(A-C) d)-b^2 (B c+(A-C) d)\right ) x+\frac {3}{8} \left (16 b \left (a^2 B-b^2 B+2 a b (A-C)\right ) d^3+(b c-a d) \left (8 b (A b+a B-b C) d^2+(b c-a d) (b c C-2 b B d-a C d)\right )\right ) x^2}{\sqrt {a+b x} \sqrt {c+d x} \left (1+x^2\right )} \, dx,x,\tan (e+f x)\right )}{6 b d^2 f}\\ &=\frac {\left (8 b (A b+a B-b C) d^2+(b c-a d) (b c C-2 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{8 b d^2 f}-\frac {(b c C-2 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{4 d^2 f}+\frac {C (a+b \tan (e+f x))^{3/2} (c+d \tan (e+f x))^{3/2}}{3 d f}+\frac {\operatorname {Subst}\left (\int \left (-\frac {3 \left (a^3 C d^3-3 a^2 b d^2 (c C+2 B d)+3 a b^2 d \left (c^2 C-4 B c d-8 (A-C) d^2\right )-b^3 \left (c^3 C-2 B c^2 d+8 c (A-C) d^2-16 B d^3\right )\right )}{8 \sqrt {a+b x} \sqrt {c+d x}}+\frac {6 \left (b d^2 \left (a^2 (A c-c C-B d)-b^2 (A c-c C-B d)-2 a b (B c+(A-C) d)\right )+b d^2 \left (2 a b (A c-c C-B d)+a^2 (B c+(A-C) d)-b^2 (B c+(A-C) d)\right ) x\right )}{\sqrt {a+b x} \sqrt {c+d x} \left (1+x^2\right )}\right ) \, dx,x,\tan (e+f x)\right )}{6 b d^2 f}\\ &=\frac {\left (8 b (A b+a B-b C) d^2+(b c-a d) (b c C-2 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{8 b d^2 f}-\frac {(b c C-2 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{4 d^2 f}+\frac {C (a+b \tan (e+f x))^{3/2} (c+d \tan (e+f x))^{3/2}}{3 d f}+\frac {\operatorname {Subst}\left (\int \frac {b d^2 \left (a^2 (A c-c C-B d)-b^2 (A c-c C-B d)-2 a b (B c+(A-C) d)\right )+b d^2 \left (2 a b (A c-c C-B d)+a^2 (B c+(A-C) d)-b^2 (B c+(A-C) d)\right ) x}{\sqrt {a+b x} \sqrt {c+d x} \left (1+x^2\right )} \, dx,x,\tan (e+f x)\right )}{b d^2 f}-\frac {\left (a^3 C d^3-3 a^2 b d^2 (c C+2 B d)+3 a b^2 d \left (c^2 C-4 B c d-8 (A-C) d^2\right )-b^3 \left (c^3 C-2 B c^2 d+8 c (A-C) d^2-16 B d^3\right )\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {a+b x} \sqrt {c+d x}} \, dx,x,\tan (e+f x)\right )}{16 b d^2 f}\\ &=\frac {\left (8 b (A b+a B-b C) d^2+(b c-a d) (b c C-2 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{8 b d^2 f}-\frac {(b c C-2 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{4 d^2 f}+\frac {C (a+b \tan (e+f x))^{3/2} (c+d \tan (e+f x))^{3/2}}{3 d f}+\frac {\operatorname {Subst}\left (\int \left (\frac {i b d^2 \left (a^2 (A c-c C-B d)-b^2 (A c-c C-B d)-2 a b (B c+(A-C) d)\right )-b d^2 \left (2 a b (A c-c C-B d)+a^2 (B c+(A-C) d)-b^2 (B c+(A-C) d)\right )}{2 (i-x) \sqrt {a+b x} \sqrt {c+d x}}+\frac {i b d^2 \left (a^2 (A c-c C-B d)-b^2 (A c-c C-B d)-2 a b (B c+(A-C) d)\right )+b d^2 \left (2 a b (A c-c C-B d)+a^2 (B c+(A-C) d)-b^2 (B c+(A-C) d)\right )}{2 (i+x) \sqrt {a+b x} \sqrt {c+d x}}\right ) \, dx,x,\tan (e+f x)\right )}{b d^2 f}-\frac {\left (a^3 C d^3-3 a^2 b d^2 (c C+2 B d)+3 a b^2 d \left (c^2 C-4 B c d-8 (A-C) d^2\right )-b^3 \left (c^3 C-2 B c^2 d+8 c (A-C) d^2-16 B d^3\right )\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {c-\frac {a d}{b}+\frac {d x^2}{b}}} \, dx,x,\sqrt {a+b \tan (e+f x)}\right )}{8 b^2 d^2 f}\\ &=\frac {\left (8 b (A b+a B-b C) d^2+(b c-a d) (b c C-2 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{8 b d^2 f}-\frac {(b c C-2 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{4 d^2 f}+\frac {C (a+b \tan (e+f x))^{3/2} (c+d \tan (e+f x))^{3/2}}{3 d f}+\frac {\left ((a-i b)^2 (A-i B-C) (i c+d)\right ) \operatorname {Subst}\left (\int \frac {1}{(i+x) \sqrt {a+b x} \sqrt {c+d x}} \, dx,x,\tan (e+f x)\right )}{2 f}-\frac {\left (a^3 C d^3-3 a^2 b d^2 (c C+2 B d)+3 a b^2 d \left (c^2 C-4 B c d-8 (A-C) d^2\right )-b^3 \left (c^3 C-2 B c^2 d+8 c (A-C) d^2-16 B d^3\right )\right ) \operatorname {Subst}\left (\int \frac {1}{1-\frac {d x^2}{b}} \, dx,x,\frac {\sqrt {a+b \tan (e+f x)}}{\sqrt {c+d \tan (e+f x)}}\right )}{8 b^2 d^2 f}+\frac {\left (i b d^2 \left (a^2 (A c-c C-B d)-b^2 (A c-c C-B d)-2 a b (B c+(A-C) d)\right )-b d^2 \left (2 a b (A c-c C-B d)+a^2 (B c+(A-C) d)-b^2 (B c+(A-C) d)\right )\right ) \operatorname {Subst}\left (\int \frac {1}{(i-x) \sqrt {a+b x} \sqrt {c+d x}} \, dx,x,\tan (e+f x)\right )}{2 b d^2 f}\\ &=-\frac {\left (a^3 C d^3-3 a^2 b d^2 (c C+2 B d)+3 a b^2 d \left (c^2 C-4 B c d-8 (A-C) d^2\right )-b^3 \left (c^3 C-2 B c^2 d+8 c (A-C) d^2-16 B d^3\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c+d \tan (e+f x)}}\right )}{8 b^{3/2} d^{5/2} f}+\frac {\left (8 b (A b+a B-b C) d^2+(b c-a d) (b c C-2 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{8 b d^2 f}-\frac {(b c C-2 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{4 d^2 f}+\frac {C (a+b \tan (e+f x))^{3/2} (c+d \tan (e+f x))^{3/2}}{3 d f}+\frac {\left ((a-i b)^2 (A-i B-C) (i c+d)\right ) \operatorname {Subst}\left (\int \frac {1}{-a+i b-(-c+i d) x^2} \, dx,x,\frac {\sqrt {a+b \tan (e+f x)}}{\sqrt {c+d \tan (e+f x)}}\right )}{f}+\frac {\left (i b d^2 \left (a^2 (A c-c C-B d)-b^2 (A c-c C-B d)-2 a b (B c+(A-C) d)\right )-b d^2 \left (2 a b (A c-c C-B d)+a^2 (B c+(A-C) d)-b^2 (B c+(A-C) d)\right )\right ) \operatorname {Subst}\left (\int \frac {1}{a+i b-(c+i d) x^2} \, dx,x,\frac {\sqrt {a+b \tan (e+f x)}}{\sqrt {c+d \tan (e+f x)}}\right )}{b d^2 f}\\ &=-\frac {(a-i b)^{3/2} (i A+B-i C) \sqrt {c-i d} \tanh ^{-1}\left (\frac {\sqrt {c-i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a-i b} \sqrt {c+d \tan (e+f x)}}\right )}{f}-\frac {(a+i b)^{3/2} (B-i (A-C)) \sqrt {c+i d} \tanh ^{-1}\left (\frac {\sqrt {c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{f}-\frac {\left (a^3 C d^3-3 a^2 b d^2 (c C+2 B d)+3 a b^2 d \left (c^2 C-4 B c d-8 (A-C) d^2\right )-b^3 \left (c^3 C-2 B c^2 d+8 c (A-C) d^2-16 B d^3\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c+d \tan (e+f x)}}\right )}{8 b^{3/2} d^{5/2} f}+\frac {\left (8 b (A b+a B-b C) d^2+(b c-a d) (b c C-2 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{8 b d^2 f}-\frac {(b c C-2 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{4 d^2 f}+\frac {C (a+b \tan (e+f x))^{3/2} (c+d \tan (e+f x))^{3/2}}{3 d f}\\ \end {align*}
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Mathematica [A] time = 8.88, size = 835, normalized size = 1.65 \[ \frac {C (a+b \tan (e+f x))^{3/2} (c+d \tan (e+f x))^{3/2}}{3 d f}+\frac {\frac {\frac {3 \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)} \left (8 b (A b-C b+a B) d^2+(b c-a d) (b c C-a d C-2 b B d)\right )}{4 b f}+\frac {\frac {6 b \left (\sqrt {-b^2} \left ((A c-C c-B d) a^2-2 b (B c+(A-C) d) a-b^2 (A c-C c-B d)\right )+b \left ((B c+(A-C) d) a^2+2 b (A c-C c-B d) a-b^2 (B c+(A-C) d)\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {\frac {\sqrt {-b^2} d}{b}-c} \sqrt {a+b \tan (e+f x)}}{\sqrt {\sqrt {-b^2}-a} \sqrt {c+d \tan (e+f x)}}\right ) d^2}{\sqrt {\sqrt {-b^2}-a} \sqrt {\frac {\sqrt {-b^2} d}{b}-c}}+\frac {6 b \left (\sqrt {-b^2} \left ((A c-C c-B d) a^2-2 b (B c+(A-C) d) a-b^2 (A c-C c-B d)\right )-b \left ((B c+(A-C) d) a^2+2 b (A c-C c-B d) a-b^2 (B c+(A-C) d)\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {c+\frac {\sqrt {-b^2} d}{b}} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+\sqrt {-b^2}} \sqrt {c+d \tan (e+f x)}}\right ) d^2}{\sqrt {a+\sqrt {-b^2}} \sqrt {c+\frac {\sqrt {-b^2} d}{b}}}-\frac {3 \sqrt {b} \sqrt {c-\frac {a d}{b}} \left (-\left (\left (C c^3-2 B d c^2+8 (A-C) d^2 c-16 B d^3\right ) b^3\right )+3 a d \left (C c^2-4 B d c-8 (A-C) d^2\right ) b^2-3 a^2 d^2 (c C+2 B d) b+a^3 C d^3\right ) \sinh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c-\frac {a d}{b}}}\right ) \sqrt {\frac {b c+b d \tan (e+f x)}{b c-a d}}}{4 \sqrt {c+d \tan (e+f x)} \sqrt {d}}}{b^2 f}}{2 d}-\frac {3 (b c C-a d C-2 b B d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{4 d f}}{3 d} \]
Antiderivative was successfully verified.
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fricas [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F(-1)] time = 180.00, size = 0, normalized size = 0.00 \[ \int \sqrt {c +d \tan \left (f x +e \right )}\, \left (a +b \tan \left (f x +e \right )\right )^{\frac {3}{2}} \left (A +B \tan \left (f x +e \right )+C \left (\tan ^{2}\left (f x +e \right )\right )\right )\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (C \tan \left (f x + e\right )^{2} + B \tan \left (f x + e\right ) + A\right )} {\left (b \tan \left (f x + e\right ) + a\right )}^{\frac {3}{2}} \sqrt {d \tan \left (f x + e\right ) + c}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int {\left (a+b\,\mathrm {tan}\left (e+f\,x\right )\right )}^{3/2}\,\sqrt {c+d\,\mathrm {tan}\left (e+f\,x\right )}\,\left (C\,{\mathrm {tan}\left (e+f\,x\right )}^2+B\,\mathrm {tan}\left (e+f\,x\right )+A\right ) \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (a + b \tan {\left (e + f x \right )}\right )^{\frac {3}{2}} \sqrt {c + d \tan {\left (e + f x \right )}} \left (A + B \tan {\left (e + f x \right )} + C \tan ^{2}{\left (e + f x \right )}\right )\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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